Staring at loops

General
#1

hi all,
i have this head breaker puzzle that i can use help in solving. I have been staring at it and trying a few hours now and my vision has become blurred.
It has to do with a loop in a loop.

i’m afraid to show one of my test codes here, because i know this is (very) bad…
Perhaps for someone this is a piece of cake?

What is my goal: create an i-rate loop.

  • have ixstart loop and print it (ixstart += 1) until it has reached 5- i know this one
  • then move on and add 2 to it. That makes it 7- doable as well
  • go back and do this 3 times (or more)- now things start to blur…

the result should be: 1,2,3,4,5, 7,8,9,10,11, 13,14,15,16,17, …etc

(Under pressure i am willing to show my bad code)

#2

hi menno -
something like this? best -
joachim

instr 1
iStart = 1
iNumLoops = 5
iThisLoop = 0
iArr[] init 5
while (iThisLoop < iNumLoops) do
indx = 0
while (indx < 5) do
iArr[indx] = iStart+indx
indx += 1
od
printarray(iArr)
iThisLoop += 1
iStart += 6
od
endin

#3

hmm indendation is ruined in the email — so here once again attached.

test2.csd (713 Bytes)

#4

Great code, but not what i was looking for :blush:
although i can see the beauty of using arrays, it also obliges me to study how arrays work before continuing the project i am working on. Maybe this is the time for this study, because one thing leads to another…not sure yet.

I was hoping / looking for something more old skool, so code based on adding and loops without arrays.

So output should be, if 5 values are to be printed, the 6th skipped, then go on counting another 5 starting at 7, skip one value after 11 , etc etc until i say: stop at 100 for example
1,2,3,4,5, 7,8,9,10,11, 13,14,15,16,17, 19,20,21,22,23, 25…100

I think this would take yet another loop construction to replace the counting of the array.
I will start by creating one loop and looping that loop. If i still understand what is happening, i will add yet another loop.

Thanks, Joachim, for your code.
I fear the come has come to start the array study :grinning: I am sure it will pay off in the long run

#5

yeah if it is only about printing, the solution without arrays is
perhaps simpler.
we can count from 1 to 100 and after 5 values stop printing for one number.
not sure i missed something, but you can compare the code attached.

test2.csd (1.28 KB)

#6

wow, you really control this. Nice to see.

This is definitely better readable for me. And a soft introduction to the array world. Thanks!
Something to build upon.

#7

your question was interesting for me, too.
meanwhile i realized that there is a much simpler version with arrays:

instr 1
iNumbers[] = fillarray(1,2,3,4,5)
while (iNumbers[0] < 100) do
printarray(iNumbers)
iNumbers += 6
od
endin
schedule(1,0,0)

perhaps even more motivation for you to approach this field. and cs7
will probably offer some new facilities.

j

#8

this is close to art, Joachim.
The aesthetics of it is yet another motivation!