[Csnd] syntax issues

The Csound Mailinglist
1

If I may I have some questions regarding the syntax of Csound.

1.
What is the function of the following call with the fractional instrument number?
schedule 1.001, iwhen, idur [, ip4] [, ip5] [...] ; (the explanation in the Csound Manual is as follows: fraction 0.001 tells that low one, but what does it mean?);

2.
Where can I find explanations on the use of the new shortcuts in the Csound syntax?
In particular - so quickly - in these specific cases?
• if (release()==1) then
• (active:k(1902)+2)
• linen:a(1,0.02,p3,0.1)
• (chnget:k("volume"))

Thanks for any help…
E

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2

Adding a fractional instrument number can give you greater access to individual instances. You can start N instances of instrument 1, all with a unique ID.

schedule 1.001, iwhen, idur [, ip4] [, ip5] […] ;

schedule 1.002, iwhen, idur [, ip4] [, ip5] […] ;

schedule 1.003, iwhen, idur [, ip4] [, ip5] […] ;

schedule 1.004, iwhen, idur [, ip4] [, ip5] […] ;

schedule 1.005, iwhen, idur [, ip4] [, ip5] […] ;

It can also be used for tying notes, but I’ve never done this, so can’t comment on how that works. I find it most useful when I have to disable certain instances of an instrument. In many cases I only want to disable a single instance of instrument N but can’t do so unless I give each instance a unique ID via a fractional part.

Where can I find explanations on the use of the new shortcuts in the Csound syntax?
In particular - so quickly - in these specific cases?
• if (release()==1) then
• (active:k(1902)+2)
• linen:a(1,0.02,p3,0.1)
• (chnget:k(“volume”))

Any opcode with a single output can be called using functional syntax. “if (release()==1) then” in long form is this:

k1 release
if k1 == 1 then

linen:a(1,0.02,p3,0.1) in long form is this:

aOut linen 1, 0.02, p3, 0.1

Although Csound will try to use the correct rate of the opcode, it’s good practice to explicitly state the rate using the : operator, as in linen:k(), vs linen:a()

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